x^2+10x-49^2=0

Solution for x^2+10x-49^2=0 equation:

x^2+10x-49^2=0

We add all the numbers together, and all the variables

x^2+10x-2401=0

a = 1; b = 10; c = -2401;
Δ = b2-4ac
Δ = 102-4·1·(-2401)
Δ = 9704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9704}=\sqrt{4*2426}=\sqrt{4}*\sqrt{2426}=2\sqrt{2426}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{2426}}{2*1}=\frac{-10-2\sqrt{2426}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{2426}}{2*1}=\frac{-10+2\sqrt{2426}}{2}
$